A vector A is directed along x-axis is to be added to vector B which has a magnitude of 7.0m.The sum is a third vector which is directed along y-axis with a magnitude that is 3.0 times of vector A. What is that magnitude of A?
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Let magnitude of vector A = x
Given that resultant of A+B is in positive y direction with 3x magnitude, hence B must be = -xi + 3xj
magnitude of B is also given as 7, hence
magnitude of B = √(x^2 +9x^2) = 7
√10 x =7
x = 7/√10 Ans
Explanation: see the attached drawing you can understand. Always try to break vectors in x-y directions and then balance/equate.
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