A vector field A is conservative. It can always be written as
Answers
Answer:
del cross A =0
dA /dt =0 del cross a becomes zero
Answer:
The essential business of a conservative velocity vector, also known as a route vector field, relies on only the terminals of any curve C. The route that C takes to get from its beginning point to its final location has no bearing on the integral. The this double conservative vector field F(x,y)= (x,y) is shown in the applet.
Explanation:
A vector field that is the gradient of a certain function is said to be conservative. The essential business of a conservative vector field does have the characteristic of being path independent, meaning that it doesn't matter which path is taken to connect two points. The electric field vector beneath the line integral must be conservative in order for the line total to be route independent. In addition to being irrotational, a conservative state vector also exhibits decreasing curl in 3 components. Given that the area is simply interconnected, an unsteady vector field is unavoidably conservative.
Conservative vector fields occur spontaneously in mechanics because they are forces of physical systems that save energy. It is possible to describe energy stored that is independent of any specific path followed since, for a conservative system, the effort required to go along a path in a coordinate space relies only on the route's terminals.
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