A vector in x-y plane has a magnitude 30 unts & makes con angle 37° with se-axis. The vector can be written a a as-
Answers
Answered by
0
Answer:
∴ option (4), (24i + 18j) is correct.
Explanation:
The unit vector along the x-axis is i and its magnitude is 1
1. The given vector is (24i + 24j)
Magnitude of the vector
= √(24² + 24²) ≠ 30
2. The given vector is (18i + 24j)
Magnitude of the vector
= √(18² + 24²) = 30
If θ be the angle between i and (18i + 24j), then
θ = cos⁻¹ [ { (18i + 24j) . i } / 30 * 1 ]
= cos⁻¹ (18/30) ≈ 53.13°
3. The given vector is (18i + 18j)
Magnitude of the vector
= √(18² + 18²) ≠ 30
4. The given vector is (24i + 18j)
Magnitude of the vector
= √(24² + 18²) = 30
If θ be the angle between i and (18i + 24j), then
θ = cos⁻¹ [ { (24i + 18j) . i } / 30 * 1 ]
= cos⁻¹ (24/30) = 37°
∴ option (4), (24i + 18j) is correct.
Similar questions