Question

A vector is given by 6Π-8ĵ +4K̂
Find the vector which is antiparallel to the given vector having magnitude of sqrt 58 units.

Answer 1

the vector is $\sqrt{ \frac{58}{116}} (-6i+8j-4k)= \frac{ (-6i+8j-4k)}{ \sqrt{2} }$

Answer 2

Anti parallel means negative of the given one.i.e.,(-6i+8j-4k)
the required vector=(-6i+8j-4k)*(58)^1/2/[((-6)^2+8^2+(-4)^2)]^1/2
                              =(-6i+8j-4k)*(58/116)1/2
                              =(-6i+8j-4k)*(1/2)^1/2
therefore,vector anti parallel to given vector=(-6i+8j-4k)/(2^1/2)