Question

A vector lying in X-Y plane has magnitude 10 and
makes angle 53' with the X-axis. Its Y component
will be​

Answer 1

Answer:

8

Explanation:

Y component will be 10 sin 53

10 sin 53=10×4/5

=>4×2=8

Answer 2

Answer:

10sin 53 or 8 is the Y-component.

Explanation:

Since, from the question we get that the vector is making 53 with the x-axis so the angle it will make with the y-axis will be 47 degree but we do not need that.

To find the component of x-axis will be magnitude of the vector with cosx where x is that angle so x component is 10cos53.

While the Y component will be 10 sin 53

10 sin 53=10×4/5.

Which on solving we will get 4×2=8.