Question

A vector of length 10 units makes an angle of 60 degree with vector B of 6 units find the magnitude of vector difference A-B and angle it makes with vector A

Answer 1

|A|= 10

|B| = 6

|A-B| = √(A² + (-B) ² -2ABcos(120))

=√ (100+36 + 10*6)

=√(196)= 14

Consider triangle OAR

cosΦ = 10/14

Φ = cos-¹ (10/14)