Physics, asked by bookworm95, 8 months ago


A vector of magnitude 10 has its rectangular components as 8 and 6 along x and y axes. Find
the angles it make with these axes.

Answers

Answered by kumarguptaabhi20
1

Explanation:

Given:

Magnitude of the vector=10 units

Rectangular components of the vector=8 along x axis and 6 along y axis

To find:

We have to find the angle made by the vector at x and y axis

Solution:

Let Angle made with x-axis = \alpha=α

Therefore

\ {Tan} \alpha= Tanα= =\frac{6}{8}=

8

6

=\frac{3}{4}=

4

3

\alpha=37^{\circ}α=37

Let Angle made with y-axis =\beta

\tan \beta=tanβ= =\frac{8}{6}=

6

8

=\frac{4}{3}=

3

4

\beta=53^{\circ}β=53

Answered by kalaiselvipalnimuthu
2

Answer:

Explanation:

Component along x-axis,

10cosα=8...............................(1)

Component along y-axis,

10sinα=6.................................(2)

Diving equation 2 by 1,

cosα

sinα

​  

=  

8

6

​  

 

tanα=  

4

3

​  

 

α=tan  

 

4

3

​  

 

=36.869  

0

 

Angle made with x-axis =36.869  

0

 

Angle made with y-axis =90  

0

−36.869  

0

=53.13  

0

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