Question

a vector of magnitude 10 has its rectangular components as 8 and 6 along x and y axis .find the angle it makes with this component

Answer 1

The given vector can be expressed as

$\bold{V}=8\bold{i}+6\bold{j}$.

The angle $\bold{V}$ makes with the x-component is

$\theta = \tan^{-1}(\frac{6}{8} )\\ \theta = \tan^{-1}(\frac{3}{4} )\\ \theta =36.87^o$

The angle $\bold{V}$ makes with the y-component is

$90^o-36.87^o=53.13^o$

Answer 2

Step-by-step explanation:

Angle along x-axis will be

                       Theta = Tan^-1 {6/8}

                                  = Tan^-1 {3/4}

                                  = 36.87 Degree

Angle along y-axis will be

                       Theta = Tan^-1 {8/6}

                                  = Tan^-1 {4/3}

                                  = 53.13 Degree