Question

A vector of magnitude 10 units perpendicular to a=i+j-k and coplanar with the vectors b=2i-j-k and c=i+2j-k is

Answer 1

Answer:

(-5.85)x+(7.8)y+1.95z.

Step-by-step explanation:

Since, the three vectors are given as a,b,c. So, we take the vector which is having a magnitude 10 to be xi+yj+zk. So, we get that this vector and the a vector is perpendicular to each other. So, their dot product will be zero.

Again, the given 3 vectors are coplanar hence r.(bxc) will be also 0.