Question

A vector of magnitude 100 N is inclined at an angle of
30° to another vector of magnitude 50 N. Calculate the
magnitude of dot product.
​

Answer 1

A . B = AB cos theta

= 5000 × √3/2

= 2500×√3

= 4330.12703

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Answer 2

Answer:

Given :

▪ Manitude of vector A = 100N

▪ Magnitude of vector B = 50N

▪ Angle b/w A and B = 30°

To Find :

❄ Magnitude of dot product and cross product.

Formula :

⚽ Dot product of two vectors :

⚽ Cross product of two vectors :

✴  = unit vector (perpendicular to the plane of vectors A and B)

Calculation :

☣ Dot product :

☣ Cross product :

Explanation: