Question

A vector of magnitude 13 makes an angle 65.37° with the x-axis. What is its component along
positive y-axis​

Answer 1

Explanation:

Answer. So, the component along positive y- axis is 11.81A vector of magnitude 13 makes an angle 65.37 degree with x axis . What is its component along positive y axis?

We have given that a vector of magnitude 13 is making an angle 65.37 degree with the x-axis.(the following image is taken from internet)

The magnitude of the vector=13.

The angle inclined by the vector on x-axis=65.37 degree.

We know that the component of this vector on x axis will be

= 13*cos(65.37)

=13*0.4167

=5.4178

and the vertical or component on the y-axis will be

=13*sin(65.37)

=13*0.9090

=11.81723

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The x and y components of a vector are 4√3m and 4m respectively. What angle does the vector make with a positive x axis?

Two perpendicular forces of magnitude 10N and 5N act at a point. What is their resultant?

A force of 10N makes an angle of 30° with y-axis. What will be the magnitude of x-component?

The X and Y components of vector are4√3m and 6 m, what angle does the vector make with positive X axis?

A vector in the XY plane has a magnitude of 25 m and an X component of 12 m. What is the angle it makes with the positive X axis?

If the magnitude of a vector is ‘a’ and it makes an angle θ with the x-axis then the projection of that vector along x-axis will be a * cos θ.

Also, projection of that vector along y-axis will be a * sin θ.

So, component of the given vector along y-axis is:

= 13 * sin (65.37°)

= 13 * sin (65.37°)

= 13 * 0.9090

= 11.8172

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v⃗ =m[cosθsinθ]=13[cos65.37∘sin65.37∘]≈[5.4211.82]

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LATEX composed at

23 sin 65.37° is the copnent along positive direction of the y axis

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13cos(65.37)

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