a vector perpendicular to i^+ j^+k^ is
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Answer:
(i + j + k) dot (A i + B j + C k) = zero
A + B + C = 0 taking the dot product
A =1, B = 1, C = -2
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Let a be vector ⊥ to i^ + j^ +k^
a=xi^+y j^ +z k^
⇒ a .( i^+ j^+k^)=0
⇒ x+y+z=0
x=3y=2j=−53+2−5=0.
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