Question

A vector Q which has a magnitude of 8 is added to the vector P which lies along the X-axis. The resultant of these two vectors is a third vector R which lies along the Y-axis and has a magnitude twice that of P The magnitude of p is
A) 6/root 5
B) 8/root 5
C) 12/root 5
D) 16/root 5
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Answer 1

Answer:

Let the P be xi^. Then the Q has to be −xi^+2x j^to make the resultant vector in y - direction and double the magnitude of P

Now, magnitude of P is x.

Using (x²+4x²) = 8 (here magnitude of Q is 8)

x= 8/√5

the correct answer is b

Explanation:

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