A vector vecA points vertically upward and vecB points towards north. The vector produce vecAxxvecB is
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Now we have two vector ie vecA and vecB . Now it is given that vecA is directed upwards and vecB points towards the North .
•) Now we have to find the direction of the third vector say vecC such that vecC = vecA×vecB.
•) Now direction of vecA is upward hence let its directional unit vector be k (Z axis) . Similarly vecB is directed towards North so let its directional unit vector be j (Y axis).
•) Now we know that in cross product,
vecC = vecA×vecB = a*b*sinΦ*(k×j)
Where, a and b are the magnitudes of vectors A and B . And Φ is the angle between them ie 90°.
•) Now in vector product we know that k×j = -i
Hence , direction of vecC will be towards negative X axis ie towards west .
•) Hence vecC = -a*bsin90
vecC = -ab