A vehical is moving on a circular track of radius 56m. It completed 3.5 rounds and then stopped. Find the distance and displacement.
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Answered by
2
solution.
Circumference of circle = 2pi r
= 2*22/7*56
= 44*8
= 352 m.
Now, distance covered in 3.5 round= 352* 3.5
= 1232 m
Now, displacement in 3.5 roumd= 56+ 56
= 112 m
___________
hope it helps you☺✌✌
Circumference of circle = 2pi r
= 2*22/7*56
= 44*8
= 352 m.
Now, distance covered in 3.5 round= 352* 3.5
= 1232 m
Now, displacement in 3.5 roumd= 56+ 56
= 112 m
___________
hope it helps you☺✌✌
Answered by
1
radius =56m
no.of rounds3.5
circumference =2πr
=2.22/7.56 =2×22×8=352
distance =3.5×352=1232.
displacement=daimeter of the circle=56+56=112m.
no.of rounds3.5
circumference =2πr
=2.22/7.56 =2×22×8=352
distance =3.5×352=1232.
displacement=daimeter of the circle=56+56=112m.
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