Physics, asked by arkalburgi, 11 months ago

a vehicle accelerates steadily from 8 km/hr to 24 km/hr in 4 second find out acceleration and the distance travelled during this period​

Answers

Answered by Anshimish0105
2

a=(v-u/t)

V=24km/hr= 24×5/18=20/3m/s

U=8km/hr=8×5/18=20/9m/s

T=4 sec

A= 20/3-20/9÷4=9/4m/s square

Distance travelled=speed × time

20/9×4=80/9m

Answered by snehayadav85
0

Explanation:

u=8km/hr

=8*5/18=20/9m/s

v=24

=24*5/18

=12/3m/s

t=4s

a=v-u

t

12/3-20/9

4

=16/9

4

=16/9*1/4

=4/9m/s2

s=ut+1/2at2

=20/9*4+1/2*4/9*4*4

=5/9+32/9=37/9m

please check the answer


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