a vehicle accelerates steadily from 8 km/hr to 24 km/hr in 4 second find out acceleration and the distance travelled during this period
Answers
Answered by
2
a=(v-u/t)
V=24km/hr= 24×5/18=20/3m/s
U=8km/hr=8×5/18=20/9m/s
T=4 sec
A= 20/3-20/9÷4=9/4m/s square
Distance travelled=speed × time
20/9×4=80/9m
Answered by
0
Explanation:
u=8km/hr
=8*5/18=20/9m/s
v=24
=24*5/18
=12/3m/s
t=4s
a=v-u
t
12/3-20/9
4
=16/9
4
=16/9*1/4
=4/9m/s2
s=ut+1/2at2
=20/9*4+1/2*4/9*4*4
=5/9+32/9=37/9m
please check the answer
Anonymous:
hii
Similar questions