Question

a vehicle changes speed from 7.5m/s to 8.5m/s in 10 seconds.find acceleration​

Answer 1

Answer:

A=Final velocity - Initial velocity

Time

A=8.5-7.5

10

A=1/10ms–²

Thanks dena please..❤❤❤

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=0.1\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Initial \: speed(u) = 7.5 \: m/s \\ \\ \tt: \implies Final \: speed(u) = 8.5 \: m/s \\ \\ \tt: \implies Time (t)= 10 \: sec\\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Acceleration(a) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 8.5 = 7.5 + a \times 10 \\ \\ \tt: \implies 8.5 - 7.5 = a \times 10 \\ \\ \tt: \implies 1 = a \times 10 \\ \\ \tt: \implies a = \frac{1}{10} \\ \\ \green{\tt: \implies a = 0.1 { \: m/s}^{2} } \\ \\ \green{\tt\therefore Acceleration \: of \: vehicle \: is \: 0.1 \: {m/s}^{2} }\\\\ \blue{ \bold{Some \: related \: formula}} \\ \orange{\tt \circ \: {v}^{2} = {u}^{2} + 2as} \\ \\ \orange{\tt \circ \: s = ut + \frac{1}{2} {at}^{2} }$