Physics, asked by prasoonjha18, 10 months ago

"A vehicle covers a distance of 40 km in first hour and a distance of 60 km in second hour of its motion. its average speed of motion is."

One expert replied it '50 kmph' but a boy in my class assumed that because of 40 km in 1 hour, speed1 is 40 kmph and because of 60 km in 1 hour, speed2 is 60 kmph and then he used a new formula for average speed Average Speed = \frac{(2*Speed1*Speed2)}{(Speed1+Speed2)} to get the answer as 48 kmph and my teacher said it as the correct one. Please explain how? 

The question above is the same copied question from my teacher's quiz so please don't complain that I have written the wrong question.

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Answers

Answered by vedant9905
15

Answer:

It is 50 km/hr

Explanation:

First take the total time, then remove the speed of 1st hour and 2nd hour which would be 40 km/hr and 60 km/hr

speed = distance/time

therefore, 1st speed = 40/1 = 40 km/hr

2nd speed = 60/1 = 60 km/hr

then avg. speed = total distance / total time taken

i. e. avg. speed = 100/2

= 50 km/hr

hence, explained

Pls mark as BRAINLIEST if you are satisfied

Answered by ananyaofficial04
3

Answer:the answer is 50 kmph

thank you

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