Question

A vehicle decelerates from 68m/s to 16 m/s in 8 sec . Calculate the deceleration and the distance covered in that time.

Answer 1

u = 6m/s

v = 16m/s

t = 10s.

a = v-u/t

a = 16-6/10

= 10/10

a = 1m/s²

distance =?=s

We know that,

2as = v²-u²

2(1)(s) = (16)²-(6)²

2s = 256-36

2s = 220

s = 110

hope it helps you ❤️✌️

Answer 2

u= 68m/s

v = 16m/s

t = 8s

a = v-u/t

a = 68-16/8

a = 52/8 m/s^2 = 6.5 m/s^2

s = ut + 1/2at^2

s = 68×8 + 1/2 × 52/8 × 8×8

s = 544 + 208 = 752 m