Question

A vehicle has a mass of 1500kg
What must be the force between
the vehicle and the road it the
schicle is to be stopped with a
negative acceleration of 1.7 ms
(ARS - 2550 N in a direction.
Opposite to that of the motion
of the vehicle)
​

Answer 1

Answer:

We know

$\sf{Force} = ma$

$\sf{Magnitude\;of\;Force} = 1500×1.7$ $= \sf 2550 N$

$\sf{F} = \sf{1500 x (-1.7)}$ = -2550N

Hence -2550N is to be applied in the opposite direction to that of the vehicle's motion in order to stop

Answer 2

AnswEr :

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• The force applied by the vehicle = 2550 N.

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Explanation :

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It is given that, the mass of a vehicle and the acceleration produced by the vehicle, that is,

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• Mass of vehicle, m = 1500 kg.

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• Acceleration produced by vehicle, a = -1.7 m/s².

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We are supposed to find the force applied bt the vehicle.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━

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We will find the force applied by the vehicle by 2nd law of Newton.

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By using the second law of Newton :

$\bf{\dag}\boxed{\bf{F = ma}}$

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Where we have the values as :

• F = unknown.
• m = 1500 kg.
• a = -1.7 m/s².

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Substituting all the given values :

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$\sf{:\implies F = 1500 \times (-1.7)} \\ \\ \\ \sf{:\implies \boxed{\frak{ \pink{{F = - 2550}}}}}$

The negative sign indicate that the direction of vehicle is opposite.

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$\sf{\therefore \underline{The \: force \: applied \: by \: the \: vehicle \: is \: \textsf{\textbf{2550 N.}}}}$