A vehicle is moving at a speed of 8 m/s. When brakes are applied, it produces a retardation of 4 m/s2. Find the braking distance for the vehicle. [ Ans. 8 m ]
Answers
Answered by
0
Answer:
Stopping/ braking distance = v*v/2a ( v= initial velocity, a= retardation )
Therefore s= 64/ 8= 8 m
Answered by
0
Answer:
8m
Explanation:
from the given data time required to stop is 2 seconds then from the equation of motion s = ut + 1/2at^2 the distance is 8m
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