A vehicle is moving in a straight line. The velocity at time t seconds after the vehicle starts is given by V = A(t−0.05t^2)for 0 ≤ t≤ 15. What is the value of A?
step by step answer please as I am getting confused with equating A.
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Given in the question,
Velocity Vms at time t second, V = A(t-0.05t²)
Integrated from 0 to 15
225A (0.5 - 0.05 × 5)
225A (0.5 - 0.25)
225A (0.25)
56.25A
To calculate the value of A =
A = 4
The value of A would be 4.
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