Question

A vehicle is moving in straight line. The velocity Vms-1 & at time t seconds after the
vehicle starts is given by V= A(t-0.05t2) for 0

Answer 1

The value of A is 5A.

V = A (t-0.05t²) (Given)

When velocity = 0, then  -

A ( t - 0.05t² ) = 0

t - 0.05t² = 0

t = 0.05t²

t = 0, t = 1/0.05

t = 0 , t = 20

Thus,  when the graph will be drawn, the resulting graph will be quadratic graph.

dv/dt = A [ 1 - 0.1t]

dv/dt = 0

T = 10 sec, thus the velocity -

v (10) = [ 10 - 0.05 (10)²]

v (10) = [ 10-5]

v(10) = 5

= 5A

Thus, the value of A is 5A.