A vehicle is moving on a road with an acceleration=20 m/s^2. The frictional coefficient between the block of mass m and the vehicle so that the block does not fall downward is?
Answers
Answered by
262
As the mass not fallen down so, the net force will be zero.
We know,
fr = mg
F = R
Fr = μR
and μ is frictional coefficient
fr = mg
μR = mg
μma = mg
μ = g/a
μ = 10/20
μ = 0.5
We know,
fr = mg
F = R
Fr = μR
and μ is frictional coefficient
fr = mg
μR = mg
μma = mg
μ = g/a
μ = 10/20
μ = 0.5
Answered by
65
Answer:
0.5
Explanation: i hope it will clear your doubt
Attachments:
Similar questions