Question

A vehicle is moving on a straight level road with a constant speed 10m/s. Due to application of brakes, it comes to rest in 5s. Find the deceleration

Answer 1

if any body is in constant velocity then , it covers equal distance in equal interval of time .


or
using
v=u+at
10=0+a×5
a=10/5
a=2m/s²
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Answer 2

Given:

• Body at speed of 10 m/s comes to rest in 5 seconds.

To find:

• Deceleration of the object ?

Calculation:

First of all, the question clearly states that the application of brakes have provided a constant deceleration.

So, let the acceleration be 'a' .

Now, applying EQUATIONS OF KINEMATICS:

$v = u + at$

$\implies \: 0 = 10 + a(5)$

$\implies \: 5a = - 10$

$\implies \:a = - 2 \: m {s}^{ - 2}$

• Since deceleration means negative acceleration, we can say :

Deceleration of the object is 2 m/s².