Question

A vehicle is moving with a velocity of 19.6 metre per second whose mass is 200 kg what is the magnitude of force required to stop the vehicle in 10 seconds?

Answer 1

Given : A vehicle is moving with a velocity of 19.6 meter per second whose mass is 200 kg

To Find : the magnitude of force required to stop the vehicle in 10 seconds

Solution:

vehicle is moving with a velocity of 19.6 meter per second

u = 19.6 m/s

v = 0  m/s   ( stop /rest )

t = 10 sec

v = u + at

=> 0 = 19.6  + a * 10

=> a = -1.96   m/s²

force required to stop  = - F

F =  ma

=> Force  required to stop  = -ma

m = 200 kg    a = -1.96  m/s²

=>  Force  required to stop = - 200(-1.96)

= 392 N

magnitude of force required to stop the vehicle in 10 seconds = 392 N

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Answer 2

Given:

A vehicle is moving with a velocity of 19.6 metre per second whose mass is 200 kg.

To find:

Force required to stop object in 10 sec?

Calculation:

Applying 1st equation of kinematics:

$\rm \therefore \: v = u + at$

$\rm \implies \: 0= 19.6+ a(10)$

$\rm \implies \: a(10) = - 19.6$

$\rm \implies \: a = - 1.96 \: m/ {s}^{2}$

Now, required force will be :

$\rm \: F = m \times a$

$\implies \rm \: F = 200 \times ( - 1.96)$

$\implies \rm \: F = - 392 \: N$

So, magnitude of force required is 392 N.

• Negative sign indicates that force vector will be opposite to initial velocity vector.