Question

a vehicle is moving with thefactorize a velocity of 50m/s how much retardation should be produced to stop the vehicle at the distance of 25m​

Answer 1

Answer:

a= -50 ( retardation )

Explanation:

u = 50m/s (given)

v =0 m/s. (given)

s =25m. (given)

using newtons third law of motion

v2-u2 =2as

0 -(50*50) = 2*a*25

-50 = a

a =50 m/s2 ( in opposite direction of force )