Question

A vehicle is moving with velocity of 19.6m/s,whose mass is 200kg

what is the magnitude of force required to stop the vehicle in 10sec?​

Answer 1

Answer :-

A retarding force of 392 Newtons is required to stop the vehicle in given time .

Explanation :-

In the question, we are given with the initial velocity, mass, and time taken by the vehicle to stop. Also, final velocity of the vehicle is 0 m/s as it ultimately stops .

Now as we know that magnitude of force is directly proportional to the rate of change of momentum, so putting values in the formula, we get :-

$\underline{\boxed{\bf{ F = \dfrac{m(v \: - u)}{t}}}}$

$\tt\implies F = \dfrac{200(0 \: - 19.6)}{10}\\\\\\\tt\implies F = \dfrac{20\!\!\!\not0(-19.6)}{1\!\!\!\not0}\\\\\\\tt\implies F = 20(-19.6)\\\\\\\tt\implies\underline{F = - \: 392 \: \: N}$

[Here, -ve sign represents retarding force] .

Answer 2

CONCEPT :-

Force is a push or pull on an object that produces acceleration in the body on which it acts.

Newton's second law of motion defines force, This law states that force is equal to the rate of change of momentum. The force on a body is equal to the product of the mass of the body and the acceleration of the body produced by the force.

Mathematically, this law is represented as

Force = mass × acceleration i.e. F = ma.

LET US DO THE QUESTION !!

QUESTION :-

• A vehicle is moving with a velocity of 19.6 metre per second whose mass is 200 kg what is the magnitude of force required to stop the vehicle in 10 seconds?

GIVEN :-

• A vehicle is moving with a velocity of 19.6 metre

• mass is 200 kg

TO FIND :-

• what is the magnitude of force required to stop the vehicle in 10 seconds = ?

SOLUTION :

first we have formula :

F = m (v -u) /t

force = 200 ( 0 - 19.6) / 10

first we will divide 200 ( 0.19.6 ) with 10

we get :

force = 200 ( -19.6) /10

then, we will again divide it we get :

force = 20 ( -19.6)

then, we will minus it we get :

force = 392

magnitude of force required to stop the vehicle in 10sec = 392 N