A vehicle is running at a speed of 45km/h .If it is stopped in 3 seconds by applying the brakes,calculate the retardation of the vehicle and the distance travelled before it's stopping.
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Answer:Initial speed u = 45 km/h = 12.5 m/s, Final speed v = 0 m/s, time t = 3 s, acceleration a.
v = u + at=> 0 = 12.5 + a(3) = a = -(12.5/3) = -4.17 m/s^2. Retardation = 4.17 m/s^2.
Distance travelled d = (1/2)(12.5)(3) = 18.75 m.
Explanation:
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