A vehicle is running uniformly on the straight road with 90 km/hour. When the driver applied
the break the bus has stopped within 10 second. Calculate the acceleration of the car and
distance travelled by the bus in the given time interval?
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u=90 * 5/18 m/s
= 25 m/s
v=0
t=10 sec
a=v-u/t
=0-25/10
acceleration = - 2.5 m/s
-ve sign signifies that the acceleration is in opposite direction to that of velocity
s=ut + 1/2at²
= 25*10 + 1/2(-2.5)10*10
= 250 - 125
distance travelled in the given time interval = 125 m
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