Question

A vehicle is traveling at 25 m/s. its brakes provide an acceleration of -3.75 m/s² (forward). what is the driver's maximum reaction time if she is to avoid hitting on obstacle 95 m away?

Answer 1

Answer:

5*95/60

Explanation:

Answer 2

Answer:

Here's your answer ,

Solution :-

Given that ,

Initial Velocity = 25m/s

Acceleration = -3.75m/s^2

Final velocity will be 0 m/s

Now , by applying third law of motion ,

=

${v}^{2} = {u}^{2} + 2as$

${0}^{2} = {(25)}^{2} + 2( - 3.75)s$

$7.5s = 625$

$s = \frac{625}{7.5}$

$s = 8.3$

So , the vehicle will not collide with obstacle.

Now , we will calculate the time taken

Applying first law of motion ,

v= u+ at

0 = 25 + (-3.75)t

-3.75t = 25

$t = \frac{25}{3.75}$

$t = 6.67$

So , the maximum reaction time will be 6.67 seconds !

Hope it helps you :)