Question

A vehicle moving in a straight line has its speed changed from 5m/s to 8m/s in 2sec. What is its average acceleration?

Answer 1

Given:

Initial Velocity= 5m/s

Final Velocity= 8m/s

time taken = 2sec

To Find:

Find the value of average acceleration.

Solution:

Average acceleration is the rate of change of velocity and it is given by;

= Change of Velocity/ Time taken

=Final Velocity- Initial Velocity/ Time

=(8 -5) / 2

=3/2

=1.5 m/s²

Hence the value of average acceleration is 1.5m/s²

Answer 2

Given,

first velocity of the vehicle $V_1 = 5 \frac{m}{s}$

second velocity of the vehicle $V_2 = 8\frac{m}{s}$

time taken to change the speed from $V_1 toV_2$ is $t = 2sec$

Now,

$Avg. acceleration = \frac{change\_in\_speed}{time\_taken}\\\\a_{avg} = \frac{V_2-V_1}{t}$

by substituting the respective values we get,

$a_{avg} = \frac{8-5}{2}\\\\ a_{avg}=\frac{3}{2}\\\\a_{avg} = 1.5 \frac{m}{s^2}$

∴The average acceleration of the vehicle is $a_{avg} = 1.5 \frac{m}{s^2}$

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