Question

A vehicle moving with a uniform acceleration of 2mls2 has a velocity of 4mls at a certain time. What will it's velocity be.
a)1s later,
b)5s later?

Answer 1

v= u + at where v is the final velocity...u is the initial velocity and t is the time...so in our given question we have .....
a=2m/s^2
u=4m/s
t=1sec
v=?
So, according to equation...v=u+at..
v=4+2×1sec...which will equal to 6m/s
now in the second part of the given question t=5sec...
so according to v=u+at,
v=4+2×5... which will equal to....14 m/s

Answer 2

Hello friend
------------------

As we all know that the distance traveled by an object in particular direction in unit time is called it's Velocity.

So,in your example.

Given:

Acceleration,a = 2 m/s^2

Initial Velocity, u = 4 m/s .....( initial velocity we have taken because work is not done,work is in progress)

So if we take your first a.) 1s later.
Means our time will consider.

Hence Time,t = 1s.

So, by using the first equation of motion
We know that,

v = u + at

Now put the given values.

we get,

v = 4 + 2*1

v = 4 + 2

v = 6 m/s.

first,Ans⏩ 6 m/s.

Similarly,we can solve the another by putting the value.

So now we take b.) 5s later.
Means our time consider

Time,t = 5s.

By using the same equation.

v = u + at

v = 4 + 2*5

v = 4 + 10

v = 14 m/s.

Second Ans⏩ 14 m/s.

........I hope this will helps you..........

Thanks.