Question

A vehicle moving with a velocity 20 m/s attains a velocity 24 m/s, after travelling a distance of 44m . Find it's acceleration

Answer 1

Answer :-

• Acceleration of the vehicle is 2 m/s².

Explanation :-

Given :

• Initial velocity (u) = 20 m/s
• Final velocity (v) = 24 m/s
• Distance (s) = 44 m

To find :

• Acceleration (a)

Solution :

Using Kinematics :

• v² = u² + 2as

Substituting we get,

⇒ 24² = 20² + 2 × a × 44

⇒ 576 = 400 + 88a

⇒ 176 = 88a

⇒ a = 176/88

⇒ a = 2 m/s²

• Acceleration of the vehicle is 2 m/s².

Answer 2

Answer:

Acceleration = 2m/s²

Explanation:

Given -

• Initial velocity (u) = 20m/s
• Final velocity (v) = 24m/s
• Distance (s) = 44m

Solution -

Acceleration (a) -

• 2as= v² - u²
• 2(44a)=24² -20²
• 88a= 576-400
• 88a = 176
• a=176÷88
• a=2

Acceleration is 2m/s² .