Question

a vehicle moving with a velocity 20ms-1 attains a velocity 24ms-1,after travelling a distance of 44m.Find it's acceleration.​

Answer 1

Answer:

• 2m/s² is the required answer.

Explanation:

Given:-

• Initial velocity ,u = 20m/s
• Final velocity ,v = 24m/s
• Distance travelled ,s = 44m

To Find:-

• Acceleration ,a

Solution:-

According to the Question

It is given that vehicle moving with a velocity 20ms-1 attains a velocity 24ms-1,after travelling a distance of 44m.

we have to calculate the acceleration of the vehicle.

Using Kinematics Equation

• v² = u² + 2as

where,

• v denote final velocity
• u denote initial velocity
• a denote acceleration
• s denote distance covered

Putting the value we get

→ 24² = 20² + 2×a × 44

→ 576 = 400 + 88×a

→ 576-400 = 88a

→ 176 = 88a

→ 88a = 176

→ a = 176/88

→ a = 2m/s²

• Hence, the acceleration of the vehicle is 2m/s².

Answer 2

Given :-

A vehicle moving with a velocity 20ms-1 attains a velocity 24ms-1,after travelling a distance of 44m

To Find :-

Acceleration

Solution :-

We know that

v² - u² = 2as

Where

v stands for Final velocity

u stands for initial velocity

a stands for acceleration

s stands for distance

(24)² - (20)² = 2a(44)

576 - 400 = 88a

176 = 88a

176/88 = a

2 = a

Hence

Acceleration is 2 m/s²