Question

a vehicle of 1 tonne travelling with a speed of 60m/s notices a cow on the road 9 m ahead applies brakes. it stops just in front of the cow . 1.find out the kinetic energy of the vehicle before applying brakes
2. calculate the retarding force provided by the brakes.​

Answer 1

Explanation:

Given A vehicle of 1 tonne travelling with a speed of 60 m/s notices a cow on the road 9 m ahead applies brakes. it stops just in front of the cow . 1.find out the kinetic energy of the vehicle before applying brakes

2. calculate the retarding force provided by the brakes.

• So kinetic energy before applying brake will be
• K.E = 1/2 mv^2
•      = 1/2 x 10^3 x 60^2
•     = 1.8 x 10^6 J
• We know that from equation of motion we get
• So v^2 = u^2 + 2as
•    0 = 60^2 + 2a(9)
•   0 = 3600 + 18a
• Or a = - 200 m / s^2
• Now retarding force F = ma
•                                     = 10^3 x 200
• Or Force F = 2 x 10^5 N

Reference link will be

https://brainly.in/question/12965782

Answer 2

a vehicle of 1 tonne travelling with a speed of 60m/s notices a cow on the road 9 m ahead applies brakes. it stops just in front of the cow .

1.find out the kinetic energy of the vehicle before applying brakes

2. calculate the retarding force provided by the brakes.

• So kinetic energy before applying brake will be.

• K.E = 1/2 mv^2

• = 1/2 × 10^3 × 60^2

• = 1/8 × 10^6 J

• We know that from equation of motion we get

• So v^2 = u^2 + 2as

• 0 = 60^2 + 2a(9)

• 0 = 3600 + 18a

• Or a = -200m/s^2

• Now regarding Force F = ma

• = 10^3 × 200

• .Or Force F = 2 × 10^5 N