Question

A vehicle of 100 kg is moving with a velocity of 5 m/sec. To stop it in 1/10sec , the required
force in opposite direction is
​

Answer 1

Answer:

5000 N

Explanation:

Force = Change in momentum / Time taken

= (mv - mu)/t

= [m(v - u)]/t

= [100 kg × (0 m/s - 5 m/s)] / (1/10 s)

= -5000 kg m/s²

= -5000 N

(Negative sign indicates that force should be applied in the direction opposite to that of direction of velocity)

Answer 2

$\large\blue{heya mate!!}$

m = 100 kg V = 5 m/s t = 0.1 sec

F = m × a = {(100 × 5) / (0.1)}

= 5000