A vehicle of 100 kg is moving with a velocity of 5m/s To stop it in 1/10s the required force in opposite direction is,
Answers
Answered by
6
u=5 m/s
v=0 m/s
t=0.1 sec
F=ma
a=v-u/t=-50 m/s^2
F=-5000 N
negative sign indicating direction in which force is applied
v=0 m/s
t=0.1 sec
F=ma
a=v-u/t=-50 m/s^2
F=-5000 N
negative sign indicating direction in which force is applied
Similar questions