a vehicle of 100kg is moving with a velocity of 5m\s. to stop 1/10s .the required force in opposite directions is
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Answer:
500 N
Explanation:
A vehicle mass of 10kg is moving with a velocity of 5ms. To stop it in 1/10th sec the required force in opposite direction is
Initial Velocity = 5 m/s
Final Velocity = 0 m/s
Time = 1/10 sec
Using V = U + at
=> 0 = 5 + a(1/10)
=> a = -50 m/s²
Force Required in opposite direction = -ma
= -10 *(-50)
= 500 N
required force in opposite direction is = 500 N
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