Question

A vehicle of mass 10kg is moving with a velocity of 2ms . Find the magnitude of the

force that is to be applied on the vehicle so that the vehicle have a velocity of 1ms

after traveling a distance of 10m.​

Answer 1

Answer:

Using the third equation of motion

v

2

=u

2

+2as

1

2

=4

2

+2

20

F

s

−15=2×

20

F

×20

F=7.5N

Answer 2

Given:

m = 10 kg

u = 2 m/s

v = 1 m/s

s = 10 m

To Find:

Force F.

Solution:

Using the third equation of motion,

${v}^{2} = {u}^{2} + 2as$

${1}^{2} = {2}^{2} + 2(a)(10)$

1 = 4 + 20a

20 a = -3

a = -3/10

Force F = ma

F = 10 × (-3/10)

F = -3 N

Negative sign indicates that a force of 3N should be applied in the opposite direction of the motion.

Force that is to be applied on the vehicle so that the vehicle have a velocity of 1 m/s after traveling a distance of 10m is 3 N.