a vehicle of mass 120kg is moving with a velocity 25m/s.what force should be applied on the vehicle to stop it in 5sec
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We know that a = (v - u)/ t
Here , u = 25 m/s
v = 0 since the vehicle comes to stop
t = 5 s
So , a = 25/5 = 5 m/s^2
Now, F = ma
F = 120 x 5
F = 600 N
Hope This Helps You!
Here , u = 25 m/s
v = 0 since the vehicle comes to stop
t = 5 s
So , a = 25/5 = 5 m/s^2
Now, F = ma
F = 120 x 5
F = 600 N
Hope This Helps You!
Answered by
2
a = (v - u)/ t
u = 25 m/s
v = 0 since the vehicle comes to stop
t = 5s
Therefore,
a = 25/5
= 5 m/s^2
Now, F = ma
F = 120 x 5
F = 600 N
u = 25 m/s
v = 0 since the vehicle comes to stop
t = 5s
Therefore,
a = 25/5
= 5 m/s^2
Now, F = ma
F = 120 x 5
F = 600 N
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