Question

A vehicle of mass 120kg is moving with a velocity of 90kmph. What force should be applied on vehicle to stop it in 5s

Answer 1

M=120kg
U=90km/h=10m/s
V=0
T=5 sec
A=v-u/t
A=-10/5
A= -2m/s2
F=ma
F= 120×(-2)
F=- 240N
Negative sign shows that force must be applied in opposite direction

Answer 2

Answer:

The force should be applied to stop in 5 seconds is = 600 N

Explanation:

Given,

The mass of the vehicle is = 120kg

The moving  velocity of =90kmph

To find,

What force should be applied to the vehicle to stop it in 5s

In Physics, the magnitude of strength guides the sum of all the forces that are acting on an object. If all the forces exist acting in the exact approach, then the magnitude of the strength increases. If the forces are acting on an object in various directions, then the magnitude of the force decreases.

$\mathrm{u}=90 \mathrm{~km} / \mathrm{h}=90 \times \mathrm{m} / \mathrm{sec}$

$=25 \mathrm{~m} / \mathrm{sec}$

Step 1

$\mathrm{v}=0 \mathrm{~m} / \mathrm{sec}$

$\mathrm{t}=55 \mathrm{a}=\frac{\mathrm{v}-\mathrm{u}}{\mathrm{t}}=\frac{0-25}{5}=-5$

Step 2

so $\mathrm{F}=\mathrm{ma}=120 \times 5$

$=600 \mathrm{~N}$

Hence, The force that should be applied to stop in 5 seconds is = 600 N

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