Question

a vehicle of mass 300 kg is moving with a velocity of 27 km/h. it then increases its velocity to 36 km/h. calculate
i) the initial kinetic energy
ii) the gain in kinetic energy




please solve



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Answer 1

Initial velocity (u) = 27 km/h = 7.5 m/s

Mass of the vehicle (m) = 300 kg

Formula for kinetic energy = $\frac{1}{2}mu^2$

i) initial kinetic energy = $\frac{1}{2}mu^2$

Plugging the values:

Initial kinetic energy = $\frac{1}{2} \times 300 \times 7.5^2$

Initial kinetic energy = 8437.5 joules

ii) Now, the final velocity (v) = 36 km/hr = 10 m/s

Final kinetic energy = $\frac{1}{2}mv^2$

Plugging the values:

Final kinetic energy = $\frac{1}{2}\times 300 \times 10^2$

Final kinetic energy = 15000 Joules

Gain in kinetic energy = Final kinetic energy - Initial kinetic energy

Gain in kinetic energy = 15000 - 8437.5

Gain in kinetic energy = 6562.5 Joules

Answer 2

Answer:

Initial velocity (u) = 27 km/h = 7.5 m/s

Mass of the vehicle (m) = 300 kg

Formula for kinetic energy = \frac{1}{2}mu^2

2

1

mu

2

i) initial kinetic energy = \frac{1}{2}mu^2

2

1

mu

2

Plugging the values:

Initial kinetic energy = \frac{1}{2} \times 300 \times 7.5^2

2

1

×300×7.5

2

Initial kinetic energy = 8437.5 joules

ii) Now, the final velocity (v) = 36 km/hr = 10 m/s

Final kinetic energy = \frac{1}{2}mv^2

2

1

mv

2

Plugging the values:

Final kinetic energy = \frac{1}{2}\times 300 \times 10^2

2

1

×300×10

2

Final kinetic energy = 15000 Joules

Gain in kinetic energy = Final kinetic energy - Initial kinetic energy

Gain in kinetic energy = 15000 - 8437.5

Gain in kinetic energy = 6562.5 Joules

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