A vehicle of the mass 120 kg is moving with velocityv90 kmph what force should be applied on vehicle to stop in 5 secs
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given, mass = 120 kg U = 90km/hr = 90*5/18
= 25 m/sec
t= 5sec and v = 0
deceleration = v-u/t
(0 - 25) /5
= - 5m/sec^2
F = m*a
= 120*(-5)= -600 N
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