A vehicle starts to move from rest and accelerates at the rate of 0.5 m/s². what is the final velocity of the vehicle after 4 minutes? how much distance is travelled by the car in this time?
koi hai
Answers
Answer:
Given :
A vehicle starts to move from rest and accelerates at the rate of 0.5 m/s².
To Find :
Final Velocity and Distance travelled by the vehicle in 4 minutes.
Solution :
\longmapsto\tt{Initial\:Velocity\:(u)=0\:m/s}⟼InitialVelocity(u)=0m/s
\longmapsto\tt{Time\:Taken\:(t)=4\:min=240\:sec}⟼TimeTaken(t)=4min=240sec
\longmapsto\tt{Acceleration\:(a)=0.5{\:m/s}^{2}}⟼Acceleration(a)=0.5m/s
2
Using 1st Equation :
\longmapsto\tt\boxed{v=u+at}⟼
v=u+at
Putting Values :
\longmapsto\tt{v=0+0.5\times{240}}⟼v=0+0.5×240
\longmapsto\tt{v=0+120}⟼v=0+120
\red\longmapsto\:\large\underline{\boxed{\bf\blue{v}\pink{=}\green{120\:m/s}}}⟼
v=120m/s
So , The Final Velocity is 120 m/s .
For Distance :
Using 3rd Equation :
\longmapsto\tt\boxed{{v}^{2}-{u}^{2}=2as}⟼
v
2
−u
2
=2as
Putting Values :
\longmapsto\tt{{120}^{2}-{0}^{2}=2\times{0.5}\times{s}}⟼120
2
−0
2
=2×0.5×s
\longmapsto\tt{14400=1s}⟼14400=1s
\longmapsto\tt\bf{s=14400\:m}⟼s=14400m
So , The Distance covered by the vehicle is 14400 m.
A vehicle starts to move from rest and accelerates at the rate of 0.5 m/s². what is the final velocity of the vehicle after 4 minutes? how much distance is travelled by the car in this time?
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