Question

A vehicle travels from the rest A and moving with the acceleration of 4m/see then find the distance travelled at 20th second in kilometers ​

Answer 1

Answer:

The distance traveled at 20th second is 0.078 Km.

Explanation:

The vehicle starts from rest. So its initial velocity, u = 0 m/s

Acceleration of the vehicle, a = 4 m/s²

The distance traveled by the vehicle in 20 seconds is:

S₂₀ = ut + (at²/2)

S₂₀ = 0 + (4 × 20² / 2)

S₂₀ = 800 m

The distance traveled by the vehicle in 19 seconds is:

S₁₉ = ut + (at²/2)

S₁₉ = 0 + (4 × 19² / 2)

S₁₉ = 722 m

So the distance traveled by the body in the 20th second is:

S = S₂₀ - S₁₉

S = 800 - 722

S = 78 m or 0.078 Km

Answer 2

Answer:

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