Question

A vehicle travels half of the distance with speed V1
and other half of distance in two equal time interval
with speed V2 and V3. The average speed of vehicle​

Answer 1

Answer:

2v1v2/ v1+ v2

Explanation:

Time taken to travel first half distance = t1 = L/2v1

Time taken to travel second half distance = t2 = L/2v2

Total time = t1 + t2

=  L/2v1 +  L/2v2

= L/2 ( 1/v1 + 1/v2)

Vavg = Total distance/Total time

=L/( L/2v1+L/2v2)

= ( L/L/2) × 1/(1/v1+1/v2)=2v1v2/v1+v2

= ( 2v1v2)/(v1+v2)

Therefore, the average speed of the vehicle is 2v1v2/ v1+ v2

Answer 2

Answer:

the correct answer is option 2

(2v1v2+2v2v3)/(2v1+v2+v3)

Explanation:

Let the total distance be s

t1 = time taken to travel first half of the total distance

time taken  = distance travel/ velocity

t1= (s/2)/v1

t1=s/2v1

time taken to travel the remaining distance is t2

s/2= (t2v2)/2 + (t2v3)/2

s= t2(v2+v3)

t2 = s/(v2+v3)

total time is t1+t2

t= s/2v1 + s/(v2+v3)

average speed is equal to = total distance/ total time taken

                                            = s/(s/2v1 + s/(v2+v3))

                                            = (2v1v2 + 2v1v3)/(2v1 + v2 + v3).

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