Question

A vehicle travels half the distance l with speed v1 and the other half with speed v2 then its average speed is - solution

Answer 1

Answer:

$average \: speed \: = \frac{ total \: distance}{total \: time} \\ \\ average \: speed = \frac{ \frac{s}{2} + \frac{s}{2} }{t1 + t2} \\ \\ average \: speed = \frac{ \frac{s}{2} + \frac{s}{2} }{ \frac{s}{2v.1} + \frac{s}{2v.2} } \\ \\ avg \: speed = \frac{2v.1v.2}{v.1 + v.2}$

Hope the answer will help

Answer 2

$\red {\boxed{average \: speed = \frac{total \: distance \: covered}{total \: time \: taken} }}$

let the distance traveled be D

$time \: taken \: in \: covering \: first \: half \\ \: distance = \frac{d}{2} (v1)$

$time \: taken \: in \: covering \: the \: second \\ \: half \: distance= \frac{d}{2} (v2)$

$\pink{total \: time \: taken = \frac{d}{2}v2 + \frac{d}{2} v1}$

$\purple{ = \frac{d(v1 + v2)}{2v1v2}}$

$\blue{so \: average \: speed = \frac{\frac{D}{D(v1+v2)}}{2v1v2}}$

$\orange{ \frac{2v1v2}{v1 + v2}}$

warm regards

@battleangel

glad if this helps you

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