A vehicle was initially moving with velocity v = 4î - 3j m/s. Then under the action of a constant force acting on it for 10s, its velocity changed to i, = 4j m/s and remained constant for the rest of the motion. The mass of the vehicle is 1000 kg.
Answers
Answer:
Mass of the body, m = 3 kg
Initial speed of the body, u = 2 m/s
Final speed of the body, v = 3.5 m/s
Time, t = 25 s
Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:
v=u+at
a=t(v−u)
=25(3.5−2)=0.06m/s2
As per Newton's second law of motion, force is given as:
F=ma
=3×0.06=0.18N
Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.
Explanation:
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Explanation:
Mass of the body, m = 3 kg
Initial speed of the body, u = 2 m/s
Final speed of the body, v = 3.5 m/s
Time, t = 25 s
Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:
v=u+at
a=t(v−u)
=25(3.5−2)=0.06m/s2
As per Newton's second law of motion, force is given as:
F=ma
=3×0.06=0.18N
Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.