Question

a velocity is inclined at 30 degree to the horizontal if the rectangular component in horizontal direction is 40 km hr find the magnitude of velocity and vertical component

Answer 1

Answer:

It is given that,

Angle between the horizontal and the force, θ = 30°

Force acting in horizontal direction, F = 50 N

We have to find the magnitude of force and its vertical components. We know that the horizontal component is F cosθ and vertical component is F sinθ.

So, Fcos(30)=50

F=57.7N

vertical component

Fsin theta =57.7 x sin(30)

Fsin theta =28.85N